CSIR UGC NET Answer Key 2020: 26 November (Mathematical & Chemical Sciences) Paper Analysis, Solutions

The NTA conducts CSIR UGC NET exam on 26 November and likely to display Answer key at website. NTA conducts CSIR NET for the last time on Thursday following the social distancing. Candidates may have a look at CSIR UGC NET paper analysis.

By Rohit Sindhu, Updated : Nov 26, 2020 16:18 IST
CSIR UGC NET Answer Key 2020: 26 November (Mathematical & Chemical Sciences) Paper Analysis, Solutions
CSIR UGC NET 2020- Demonstrative Image

The National Testing Agency (NTA) conducting the CSIR UGC NET on November 26, would display provisional Answer key. Nodal Agency shall issue CSIR UGC-NET answer key of 26th Nov held Mathematical Sciences and Chemical Sciences paper response sheet and intimation regarding challenges, at official site. Candidates appear for the Council of Scientific and Industrial Research (CSIR) UGC NET in CBT mode in shift 1 or 2, can check the availability of Answer key and solutions at site csirnet.nta.nic.in.

Nodal Agency conducts CSIR UGC NET 2020 exam for Chemical Sciences (Subject Code-701) in 1st shift and for Mathematical Sciences (subject code-704) in second shift. The examination was organized at allotted exam centres across the country (except in Tamil Nadu and UT of Puducherry). CSIR UGC NET November 26 online exam began at 9:30 AM and lasted at 12:30 pm for shift 1 and from 2.30 to 5.30 pm for shift 2. Exam held following the social-distancing and other safety instructions. Aspirants were allowed only wearing face masks/ cover inside the examination hall.

Conducting the UGC NET Paper 1 and Paper 2 online exam in respective shifts, a detailed analysis of question papers is being facilitated to help students visualize their score. NTA conducts online exam for UGC NET June 2020 scheduled on November 12. The examination was conducted in two shifts, for Education and Geography subjects.

The NTA will display the recorded responses and CSIR UGC NET June 2020 question Paper attempted by the candidates on the NTA website csirnet.nta.nic.in prior to declaration of result. The recorded responses are likely to be displayed for two to three days.

According to the information bulletin, the NTA will display provisional Answer Key of the questions on the NTA website csirnet.nta.nic.in to provide an opportunity to the candidates to challenge the provisional Answer Key. The Answer Keys are likely to be displayed for two to three days.

The Candidates will be given an opportunity to make a challenge online against the Provisional Answer Key on payment of Rs. 1000/- per question challenged as processing charges.

Should Read- CSIR UGC NET 21 November Answer Key and Paper Analysis

Exam Postponement due to 'Nivar':

Owing to cyclone "Nivar" the Joint CSIR UGC NET 2020 examination schedule on scheduled 26th November 2020, (Mathematical Sciences and Chemical Sciences) stand postponed until further notice in respect of all the examination centres in Union Territory of Puducherry and the State of Tamil Nadu. New date for examination will be notified shortly, reads official notice.

CSIR UGC NET Shift 1,2 Exam Analysis:

The first shift examination held from 09:30 am- 12:30 pm, followed by second shift examination from 02:30 pm- 5:30 pm. Candidates shall not be permitted to enter in the Examination Centre after 8.30 am in First Shift and after 1.30 pm in Second Shift.

Chemical Sciences (701)-: The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B and Part-C respectively. If more than required number of questions are answered, only first 15, 35 and 25 questions in Part A, Part B and Part C respectively will be taken up for evaluation.

Chemical Sciences Paper Analysis- Video Credit- Chemistry Learnopedia

Mathematical Sciences (704): The candidate is required to answer a maximum of 15, 25 and 20 questions from Part-A, Part-B and Part-C respectively. If more than required number of questions are answered, only first 15, 25 and 20 questions in Part A, Part B and Part C respectively will be taken up for evaluation. There is negative marking for part A, B & C is at 25%.

Note- CSIR-UGC NET is a test being conducted to determine the eligibility ‘for Junior Research Fellowship (JRF) and for Lectureship/ Assistant Professor’ in Indian Universities and colleges subject to fulfilling the eligibility criteria laid down by UGC